The value of $\lim _\limits{x \rightarrow 0} \frac{(1-x)^n-1}{x}=$ — Answer & Explanation

The value of $\lim _\limits{x \rightarrow 0} \frac{(1-x)^n-1}{x}=$

✓ Correct answer: C

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Question ID #143312 · NewNcert

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