The value of $\int \frac{\mathrm{d} x}{7+6 x-x^2}$ is equal to
- A$\frac{1}{4} \log \left(\frac{1+x}{7-x}\right)+\mathrm{c}$, (where c is a constant of integration)
- B$\frac{1}{8} \log \left(\frac{7-x}{1+x}\right)+\mathrm{c}$, ( where c is a constant of integration)
- C$\frac{1}{4} \log \left(\frac{7-x}{1+x}\right)+\mathrm{c}$, (where c is a constant of integration)
- D$\frac{1}{8} \log \left(\frac{1+x}{7-x}\right)+\mathrm{c}$, (where c is a constant of integration)
✓ Correct answer: D
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