The width of fringe is $$2 \mathrm{~mm}$$ on the screen in a double slits experiment for the light of wavelength of $$400 \mathrm{~nm}$$. The width of the fringe for the light of wavelength 600 $$\mathrm{nm}$$ will be:
- A4 mm
- B1.33 mm
- C2 mm
- D3 mm
✓ Correct answer: D
Want the full step-by-step reasoning?