Three distinct points A, B and C are given in the 2 -dimensional coordinates plane such that the ratio of the distance of any one of them from the point $$(1, 0)$$ to the distance from the point $$(-1, 0)$$ is equal to $${1 \over 3}$$. Then the circumcentre of the triangle ABC is at the point :
- A$$\left( {{5 \over 4},0} \right)$$
- B$$\left( {{5 \over 2},0} \right)$$
- C$$\left( {{5 \over 3},0} \right)$$
- D$$\left( {0,0} \right)$$
✓ Correct answer: A
Want the full step-by-step reasoning?