Two capacitances of capacity $C_1$ and $C_2$ are connected in series and potential difference $V$ is applied across it. Then the potential difference across $C_1$ will be:
- A$V\frac{C_2}{C_1}$
- B$V\frac{C_1+C_2}{C_1}$
- C$V\frac{C_2}{C_1+C_2}$
- D$V\frac{C_1}{C_1+C_2}$
✓ Correct answer: C
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