Two long straight wires P and Q carrying equal current 10A each were kept parallel to each other at 5 cm distance. Magnitude of magnetic force experienced by 10 cm length of wire P is F$$_1$$. If distance between wires is halved and currents on them are doubled, force F$$_2$$ on 10 cm length of wire P will be:
- A$$\frac{F_1}{8}$$
- B10 F$$_1$$
- C$$\frac{F_1}{10}$$
- D8 F$$_1$$
✓ Correct answer: D
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