Two particles of equal mass ' $m$ ' move in a circle of radius ' $r$ ' under the action of their mutual gravitational attraction. The speed of each particle will be ( $\mathrm{G}=$ Universal gravitational constant)
- A$\sqrt{\frac{\mathrm{Gm}}{4 \mathrm{r}}}$
- B$\sqrt{\frac{\mathrm{Gm}}{\mathrm{r}}}$
- C$\sqrt{\frac{\mathrm{Gm}}{2\mathrm{r}}}$
- D$\sqrt{\frac{4 \mathrm{Gm}}{\mathrm{r}}}$
✓ Correct answer: A
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