Two progressive waves $Y_1=\sin 2 \pi\left(\frac{t}{0 \cdot 4}-\frac{x}{4}\right)$ and $Y_2=\sin 2 \pi\left(\frac{t}{0 \cdot 4}+\frac{x}{4}\right)$ superpose to form a standing wave. ' $x$ ' and ' $y$ ' are in SI system. Amplitude of the particle at $x=0.5 \mathrm{~m}$ is $\left[\sin 45^{\circ}=\cos 45^{\circ}=\frac{1}{\sqrt{2}}\right]$
- A$\sqrt{3} \mathrm{~m}$
- B$3 \sqrt{3} \mathrm{~m}$
- C$\sqrt{2} \mathrm{~m}$
- D$2 \sqrt{2} \mathrm{~m}$
✓ Correct answer: C
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