A \(10\,\mu\mathrm F\) capacitor is charged to a potential difference of \(50\,\mathrm V\) and is connected to another uncharged capacitor in parallel. Now the common potential difference becomes \(20\,\mathrm V\). The capacitance of second capacitor is:
- A\(10\,\mu\mathrm F\)
- B\(20\,\mu\mathrm F\)
- C\(30\,\mu\mathrm F\)
- D\(15\,\mu\mathrm F\)
✓ Correct answer: D
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