If $y=\sin ^{-1}\left(\frac{1}{\sqrt{x+1}}\right)$ then $\frac{d y}{d x}=$
- A$\frac{1}{2 \sqrt{1-x}}$
- B$\frac{1}{2 \sqrt{x}(1+\sqrt{x})}$
- C$\frac{1}{2 x(1+\sqrt{x})}$
- D$-\frac{1}{2 \sqrt{x}(1+x)}$
✓ Correct answer: D
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