Let $\alpha, \beta, \gamma$ be real numbers. If $A=\left[\begin{array}{ccc}7 & 3 & \alpha \\ \beta & 1 & -11 \\ -5 & \gamma & 19\end{array}\right]$ is a $3 \times 3$ matrix satisfying $A\left[\begin{array}{c}5 \\ -13 \\ 11\end{array}\right]=\left[\begin{array}{c}-290 \\ -119 \\ 210\end{array}\right]$, then $(\operatorname{adj} A)^{-1}+\operatorname{adj} A^{-1}=$
- A
$A$
- B
$-A$
- C
$2 A$
- D
$-2 A$
✓ Correct answer: D
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