The differential equation corresponding to the family of ellipses $\frac{x^2}{a^2}+\frac{y^2}{4}=1$, where ' $a$ ' is an arbitrary constant is
- A
$x y \frac{d y}{d x}=4-y^2$
- B
$x y \frac{d y}{d x}=4-x^2$
- C
$x y \frac{d y}{d x}=x^2-4$
- D
$x y \frac{d y}{d x}=y^2-4$
✓ Correct answer: D
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