The distance of line $$3y - 2z - 1 = 0 = 3x - z + 4$$ from the point (2, $$-$$1, 6) is :
- A$$\sqrt {26} $$
- B$$2\sqrt 5 $$
- C$$2\sqrt 6 $$
- D$$4\sqrt 2 $$
✓ Correct answer: C
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Question ID #164151 · NewNcert