The general solution of the differential equation $(3 x-4 y)(d x-3 d y)+(6 d x-4 d y)=0$ is
- A
$x-2 y+\log |3 x-4 y+6|=C$
- B
$5 x-15 y-4 \log |15 x-20 y-12|=C$
- C
$5 x-15 y+14 \log |15 x-20 y-12|=C$
- D
$8 y-4 x+\log |9 x-12 y+4|=C$
✓ Correct answer: C
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