The value of ΔH° in kJ for the reaction will be CS₂(l) + 4NOCl(g) → CCl₄(l) + 2SO₂(g) + 2N₂(g) If ΔH°f(CS₂) = −x, ΔH°f(NOCl) = −y, ΔH°f(CCl₄) = +z and ΔH°f(SO₂) = −r
- Ax + 4y − z − 2r
- Br + z + 4y − x
- C2r + z + 4y + x
- Dx + 4y + z − 2r
✓ Correct answer: D
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